The area of a triangle (A=1/2bh) is 52. The triangle has h=4 and b=2x+6. Value for base of the triangle?

The height is 4 and the base is 2x+6. I need to know the value of the base of the triangle.|||A = 1/2 bh


52 = (1/2) (2x+6) (4)


52 = 4x + 12


x = 10





b = 2x + 6 = (2) (10) + 6


b = 26|||52 = 1/2(4)(2x + 6)


52 = 4x + 12


40 = 4x


10 = x





b = 2(10) + 6 = 26|||A= 1/2*b*h = 52


h = 4


52 = 1/2*(2x+6)*4


2x+6 = 52/(4*1/2)


(52/(4*1/2) - 6)/2 = x





--%26gt; x =10


b= 2x+6





b = 26|||[(4)(2x+6)/2]=52


4x+12=52


4x=40


x=40/4


x=10


b=26