How to find the value of x if 2^[log(base 4)X]=7?

How to find the value of x if 2^(log(base 4)2=7


Please show your answer to me.


OK|||2^[log(base 4)X]=7 means that





log(base 2) {2^[log(base 4)X]}= log(base2)7


log(base4)x = log(base2) 7


4^log(base4)x = 4^[log(base2)7]


x = 2^[2{log(base2)7] = 2^[log(base2)7^2] = 7^2 = 49|||x^(1/2) = 7----%26gt;x = 49|||log (base 4) 2=1/2


======================================鈥?br>

The proble;


[log(base 4) x][log2]=log7


log(base 4) x=2.8


x=4^2.8=49|||this is false|||2^[log(base 4)X]=7


taking log both sides


then


[log(base 4)X][log2]=log7


log(base 4)X=[log4]/[logx]=2log2/logx


[2log2/logx][log2]=log7


logx=[2(log2)^2]/log7


solve the right hand side %26amp; then take antilog


then x=1.6383